Nathaniel builds birds and birdhouses using lego blocks. let b represent the number of birds and h represent the number of birdhouses that nathaniel can build with his lego blocks. 43b + 215h? 3000 nathaniel wants to build 50 birds using lego blocks. how many birdhouses can he build at most with the remaining lego blocks?

At-most 3 birdhouses.

Step-by-step explanation:

Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.

We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality represents the number of birds and birdhouses Nathaniel could build.

To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.

Let us subtract 2150 from both sides of our inequality.

Let us divide both both sides of our inequality by 215.

As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.

you can't solve x because it is 2 linear equation and you only have one equation

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: