The palace of peace and accord in astana, kazakhstan, was built in 20062006. the building has a square right pyramid structure. the length of a side of the square base is 62\,\text{m}62m, and the vertical height of the pyramid is also 62\,\text{m}62m. what is the height, hh, of one of the triangular faces? round your answer to the nearest tenth.

69.3 meters.

Step-by-step explanation:

Let h be the height of one of the triangular faces.

We have been given that The Palace of Peace and Accord has a square right pyramid structure. The length of a side of the square base is 62 m, and the vertical height of the pyramid is also 62 m.  

We will use Pythagorean theorem to find the height of the triangular face (slant height) of our given square right pyramid.

As we are told that base of pyramid is square and is 62 meters and height of pyramid is 62 meters.  

Upon substituting our given values in slant height formula we will get,

Therefore, the height of the each triangular face is approximately 69.3 meters.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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