Which polynomial expression in factored form has 2 as a leading coefficient with −1, 3, and −5 as zeros?

a) 2(x + 1)(x − 3)(x + 5)
b) 2(x − 1)(x + 3)(x − 5)
c) 2x(x + 1)(x − 3)(x + 5)
d) 2x(x − 1)(x + 3)(x − 5)

First, lets find the factors that take the form (x-a), where a is the zero.

-1 is a zero. Thus, , aka , is a factor.

3 is a zero. Thus, is a factor.

-5 is a zero. Thus, , aka , is a factor.

Matching these factors with the possible answer choices, we can safely see that either A or C is possible.

x is not a factor because that means the polynomial will have a zero of 0, which is not stated in the question. This eliminates C and D.

This leaves us with answer choice A.

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: