1.state whether the relationship between the variables in the table is a direct variation, an inverse variation, or neither. if it is a direct or inverse variation, write a function to model it.

2.how do the graphs of y=1/x and y=/5x+6

compare?

Step-by-step explanation:

Left Pane

Argument

[Left Graph]: The table should be graphed to begin with. Some people don't like that idea very much, but it is a quick way to get an answer. I  took the liberty of adding 0,0

When a line goes through 0,0 the variation in this case is a direct variation. Then general equation for a direct variation is y = k*x

K is the slope. You should get 3.

m = (y2 - y1) / (x2 - x1)

Givens

Solution

Answer

Direct variation

Right Panel

Argument

The best way to show this is to (again) graph it. [Right Graph]

The last two are asymptote where if the denominator approaches these values, the hyperbola goes upwards depending on what part of the graph being observed.

The 6 has the property of moving the graph left (x + 6). And the 5 has the property of stretching the graph up and down. Note the word used is stretched not moved.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3