Amay 2000 gallup poll found that 38% of a random sample of 1023 adults said that they believe in ghosts. the standard deviation is 1.5%. what is the margin of error for this survey? determine an interval that is likely to contain the percent of all adults who believe in ghosts.

Margin of error = 0.09

Confidence interval = (0.29, 0.41)

Step-by-step explanation:

Sample size, n = 1023

p = 38%

   = 0.38

Standard deviation, σ = 1.5

Consider the level of confidence to be 95%

So, corresponding z* value for 95% confidence level = 1.96

Hence, confidence interval = p ± margin of error

                                               = 0.38 ± 0.09

                                               = (0.29, 0.47)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco