Solve for x by completing the square. 2x^2-4x+7=0

2x^2 - 4x + 7 = 0

x^2 - 2x + 3.5 = 0

x^2 - 2x = - 3.5

x^2 - 2x + 1 = 1 - 3.5

(x - 1)^2 = - 2.5

No solution because a quadratic term can't be negative.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."