Agiven line has the equation 2x + 12y = −1. what is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)? y = ( )x + 9

y = 6x + 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + 12y = - 1 into this form

Subtract 2x from both sides

12y = - 2x - 1 ( divide all terms by 12 )

y = - x - ← in slope- intercept form

with slope m = -

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = 6

Note the line crosses the y- axis at (0, 9) → c = 9

y = 6x + 9 ← equation of line

hiking down a winding trail.

step-by-step explanation:

∡ eia and ∡ kij are congruent

step-by-step explanation: