6.(q^9)^2 a. 2q^18 b. q^18 c. q^81 d. q^11 7.(6q^6)^-4 a. 6q^1296 b. 1296q^2 c. 1/1296q^24 d. 6q^-24 8. what is the value of 12x^-3 y^-1 for x = -1 and y = 5? a. -12/5 b.-10 c.-0 d.5/12

6) B. q^18

7) C. 1/1296q^24

8) A. -12/5

Step-by-step explanation:

6. (q^9)^2  

= q^(9*2)

= q^18

Answer

B. q^18

7.(6q^6)^-4  

= 1/(6q^6)^4

= 1 / 1296q^24

Answer

C. 1/1296q^24

8. What is the value of 12x^-3 y^-1 for x = -1 and y = 5?

 12x^-3 y^-1

= 12/x^3y

= 12 / (-1)^3 (5)

= 12/-5

= - 12/5

Answer

A. -12/5

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?