The swimming pool is open when the high temperature is higher than 20∘c. lainey tried to swim on monday and thursday (which was 33 days later). the pool was open on monday, but it was closed on thursday. the high temperature was 30 ∘c on monday, but decreased at a constant rate in the next 33 days. write an inequality to determine the rate of temperature decrease in degrees celsius per day, d, from monday to thursday.

30 - 3d ≤ 20

Step-by-step explanation:

The temperature on Monday was 30°.  This is where our inequality begins.

The temperature has a steady decrease; this is why we subtract.

The decrease occurs over the next 3 days; letting d represent days, this gives us 3d.

The temperature on Thursday was low enough for the pool to be closed; this means it was less than or equal to 20.  

Altogether this gives us

30 - 3d ≤ 20

To solve this, we will subtract 30 from each side:

30 - 3d - 30 ≤ 20 - 30

-3d ≤ -10

Divide both sides by -3:

-3d/-3 ≤ -10/-3  (remember that we flip the inequality symbol when we divide by a negative)

d ≥ 3.33

54/3 is 18 so 18 is your answer