!! 10 ! a westbound jet leaves central airport traveling 635 miles per hour. at the same time, an eastbound plane departs at 325 miles per hour. in how many hours will the planes be 1900 miles apart?

See below

Step-by-step explanation:

You want the sum of the distances to equal 1900 miles.

They are travelling in opposite directions and therefore the distances will add.

Let the number of hours = t

Formula

d = r*t

Solution

635*t + 325*t = 1900      combine the right

960*t = 1900                    Divide by 960

960t/960 = 1900/960

t = 1.98 hours or 1 hour and 58.8 minutes or 1 hour 58 minutes 48 seconds.

Without choices, I don't know which answer you want. Perhaps even 2 hours is (rounded) close enough        

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

the answer for this question is a= 13,622.84

step-by-step explanation: