What is the sum of the geometric series in which a1 = 7, r = 3, and an = 1,701? hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio

My best interpretation of this is that you're given a geometric progression consisting of terms, the first of which is and the last of which is . (So we don't actually know right away how many terms there are.) The common ratio between terms is . You want to find the sum of all terms.

In a geometric progression, the -th term is determined by the previous term according to

Starting with , we find

and so on. The general pattern for the -th term is then

The last term in the sequence is , so

The sum of these terms is given by

Notice that

With and , we get a sum of

d is the answer

step-by-step explanation:

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300