Acollege is selling tickets for a winter fund-raiser. one day, krissa sold 14 adult tickets and 8 student tickets for a total of $376. the next day, she sold 7 adult tickets and 11 student tickets for a total of $272. krissa wanted to find the price of one adult ticket, a, and the price of one student ticket, s. she wrote and solved the following system of equations.

Step-by-step explanation:

Let's solve this by elimination, then substitution.

x= Adult ticket

y= Student ticket

First day: 14x + 8y = 376

Second day: 7x + 11y = 272:

14x+8y=376

7x+11y=272

Divide 14x+8y=376 by -2:

-7x+-4y=-188

7x+11y=272

Eliminate both -7x and 7x:

-4y=-188

11y=272:

Add all numbers:

7y=84

Divide both sides by 7/ divide 84 by 7:

y=12

Now substitute y into one of the equations:

7x+11y=272:

7x+11(12)=272

Simplify:

7x+132=272

Subtract both sides by 132:

7x=140

Divide both sides by 7 (140/7):

x=20

Adult Tickets: $20

Student Tickets: $12

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.