7x^2-9x+5=0 find the discriminant and number of real solutions

Discriminant = -59

There are no real solutions

Step-by-step explanation:

7x^2-9x+5=0

We apply the discriminant formula

D =b^2 -4*a*c

Where a, b and c are obtained by expressing the quadratic equation in the form ax^2 +bx+c =0

D = (-9)^2 - 4*(7)*(5)  = -59

Since D <0 The solutions are complex conjugates

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

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step-by-step explanation: