What is the argument of 3 - 3i? 300° 315° 330° 345°

315°

Step-by-step explanation:

z = a+bi

The modulus is the sqrt ( a^2 +b^2)

and the argument (I call it theta)  is equal to arctan (b/a)

We have z = 3-3i

We are looking for the argument of z

theta = arctan (-3/3)

           = -45 degrees

They don't like negative arguments so add 360 degrees to it.  It is the same value, we just loop once around the circle.

-45+360 =

315

take it another

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05