What is the equation of the line, that passes through (3,-1) and (-1,5)

y = -3/2x +7/2

Step-by-step explanation:

When we have two points, we need to find the slope.

Slope is given by

m = (y2-y1)/ (x2-x1)

   = (5--1)/ (-1-3)

   = (5+1)/ (-4)

   = 6/-4

   = -3/2

We have the slope and a point

Using the point slope form of a line

y-y1 = m(x-x1)

y--1 = -3/2( x-3)

y+1 = -3/2(x-3)

They usually want the line written in slope intercept form (y=mx+b)

Distribute the -3/2

y+1 = -3/2x +9/2

Subtract 1

y+1-1 = -3/2x +9/2 -2/2

y = -3/2x +7/2

combine all like terms then its just a 2 step equation