Taylor graphs the system below on her graphing calculator and decides that f(x)=g(x) at x=0, x=1, and x=3. provide taylor some feedback that explains which part of her answer is incorrect and why it is incorrect.

The part of her answer is incorrect is that f(x)=g(x) at x=3, because this value is not in the solution of the equation f(x)=g(x)

Step-by-step explanation:

f(x)=g(x)

2x+1=2x²+1

This is a quadratic equation. Equaling to zero: Subtracting 2x and 1 from both sides of the equation:

2x+1-2x-1=2x²+1-2x-1

0=2x²-2x

2x²-2x=0

Common factor 2x:

2x(x-1)=0

Two solutions:

x=0

and

x-1=0

Solving for x: Adding 1 both sides of the equation:

x-1+1=0+1→x=1

Then f(x)=g(x) at x=0, and x=3

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.