Aperson is riding in a hot air balloon. for the first hour, the wind current is a constant 8.25 mph in the direction n37.5°e. then the wind current changes to 6.00 mph and heads the balloon in the direction s52.5°e. what is the bearing of the balloon from its starting point? round your answer to 1 decimal place.

The bearing of the balloon from its starting point = N 71.9° E

Step-by-step explanation:

To find the distance to the starting point, the wind and the height are perpendicular to each other. So, use the Pythagorean Theorem :

(Distance from the starting point)² = 8.25² + 6.00² = 112.56

⇒ Distance = 10.6 miles

Then to determine the bearing y :

Since the original bearing that the balloon set off at was N 37.5° E,  

⇒  y = 37.5° + 34.4°

       = 71.9°

Hence, The bearing of the balloon from its starting point = N 71.9° E

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

i am thinking c. sorry if im wrong .

step-by-step explanation: