Atriangle with vertices located at (−2, −2) and (4, −2) has an area of 24 square units. which is one possible location of the other vertex? a) (4, 6) b) (4, 8) c) (6, −2) d) (−10, −2)

y=mx+b

step-by-step explanation:

m slope, b y-intercept

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

arc length = radius * x ( in radians)

6 * pi = 18 * x

divide by 18 on each side

6 pi / 18 = x

pi/3 = x

the angle is pi / 3 radians

or   60 degrees