All my points to whoever can solve this 5z2−9z=−7z−5 solve the following quadratic equation by using the quadratic formula. if needed, submit your answer as a fraction reduced to lowest terms or round your answer to two decimal places. there are 2 different answers

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

Step-by-step explanation:

5z^2−9z=−7z−5

We need to get all the terms on one side (set the right side equal to zero)

Add 7z to each side

5z^2−9z+7z=−7z+7z−5

5z^2−2z=−5

Add 5 to each side

5z^2−2z+5=−5 +5

5z^2−2z+5=0

This is in the form

az^2 +bz+c = 0 so we can use the quadratic formula

where a = 5   b = -2  and c = 5

-b± sqrt(b^2-4ac)

  2a

-(-2)± sqrt((-2)^2-4(5)5)

  2(5)

2± sqrt(4-100)

10

2± sqrt(-96)

10

2± sqrt(16)sqrt(-1) sqrt(6)

10

2± 4i sqrt(6)

10

1/5 ± 2/5 i sqrt(6)

Splitting the ±

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).