Note: enter your answer and show all the steps that you use to solve this problem in the space provided. the figure shows two right trapezoids. trapezoid a b c d has right angles at b and c. angle b is adjacent to the shorter parallel side. angle c is adjacent to the longer parallel side. angle a is obtuse. angle d is acute. sides a b and c d are parallel. the sides in order of length from shortest to longest are b c, a d, a b, and c d. trapezoid r s p q has right angles at s and p. angle s is adjacent to the shorter parallel side. angle p is adjacent to the longer parallel side. angle r is obtuse. angle q is acute. sides r s and p q are parallel. the sides in order of length from shortest to longest are s r, r q, r s, and p q. the two figures shown above are congruent. identify the corresponding sides and angles.

AB = RS , BC = SP , CD = PQ , AD = RQ

m∠A = m∠R ,  m∠B = m∠S ,  m∠C = m∠P ,  m∠D = m∠Q

Step-by-step explanation:

∵ Trapezoid ABCD is congregant to trapezoid RSPQ

∴ AB = RS

∴ BC = SP

∴ CD = PQ

∴ AD = RQ

∴ m∠A = m∠R

∴ m∠B = m∠S = 90°

∴ m∠C = m∠P = 90°

∴ m∠D = m∠Q

the answer is c. 23/3

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2