Acar has an initial value of $20,000. the value then "depreciates" or decreases by 10% of its initial value each year. which equation below gives the value of the car, v, after y years? a) v= 0.10y+ 2,000 b) v= 0.10y -2,000 c) v=2,000y-20,000 d) v=-2,000y+20,000

D) v = -2,000y + 20,000.

Step-by-step explanation:

The question gives a linear relationship between two quantities.  This means that the relationship between the initial value of the car and the amount it depreciates each year is proportional, or constant.  Since the value of the car decreases by 10% of its initial value each year, then each year the value will decrease by 10% of 20,000 or 0.10 x 20000 = $2,000.  Since we know the value is decreasing each year, this amount would be subtracted from the initial value of $20,000.  So, D) v = -2,000y + 20,000 would be the only equation that represents this scenario.  

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it