Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two distinct roots.

On edge, this would be the explanation. Just use these examples but change it up!

The answer is f(x) = (x-3)²-h = (x-3-√h)(x-3+√h).

Step-by-step explanation:  We are given to write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two distinct roots.

A quadratic function with vertex having x-coordinate k takes the form of a parabola as follows:

Here, 'k' and 'h' are both real.

Since we the the x-coordinate of the vertex as 3, so k = 3.

Therefore, the quadratic function becomes

This is the required factored form of the quadratic function.

See the attached graph, where the x-coordinate of the vertex is 3 and h is taken to be 2 units.

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

you have to put the graph on here with the question

step-by-step explanation: