50 points! (i rlly need ) (algebra 1)

43.06 ft

3.20 seconds

Step-by-step explanation:

h = -16t^2 +50t +4

The maximum is at the vertex

The x coordinate for the vertex is a the axis of symmetry

The axis of symmetry is

h=-b/2a  when the equation is at^2 +bt+c

h = -50/2(-16)

   =-50/-32

   = 1.5625

The maximum is when x is at 1.5625

to find y we put this into the equation

h = -16(1.5623)^2 + 50(1.5625) +4

   = -16(2.44140625) + 78.125+4

   = -39.0625+78.125+4

   =43.0625

To the nearest hundredth

43.06 ft

The second part is to find when it hits the ground, or when h=0

0 = -16t^2 +50t +4

Using the quadratic formula

-b±sqrt(b^2 -4ac)

2a

-50±sqrt(50^2 -4*-16*4)

2*-16

-50±sqrt(2500 +256)

-32

-50±sqrt(2756)

-32

-50 + sqrt(2756)      or -50 + sqrt(2756)

-32                                          -32

-.078                                    3.20

Since time cannot be negative

3.20 seconds

answer

point o.

step-by-step explanation:

the answer is b