Let f(x)=201+9e−3x . over what interval is the growth rate of the function decreasing? (ln3/9, ∞) (−∞, ln 3/9) (ln9/3, ∞) (−∞, ln 9/3)

Third option is correct.

Step-by-step explanation:

Since we have given that

As we know that it is a logistic function, and there are two types of growth rate :

1) Increasing Growth rate .

2)Diminishing  Growth rate .

Here, Carrying capacity = 20

So, at half of its carrying capacity growth rate changes.i.e.

at y>10, there is diminishing growth rate.

AT y<10, there is increasing growth rate.

so, put y=10

so, it becomes,

So, the interval will be

Above this there will growth rate at a decreasing rate and below this the growth rate at a increasing rate.

Hence, Third option is correct.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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