All my points plz be right 8th grade math plz plz me be correct for brainliest find the quotient of the quantity negative 6 times x to the 2nd power times y to the 8th power plus 12 times x times y to the 3rd power minus 36 times x times y to the 2nd power all over 6 times x times y to the 2nd power. −6x2y8 + 12xy3 − 6 −xy6 + 2y − 6 xy6 + 2y − 6 −xy6 + 2xy − 6

-xy^6 +2y -6

Step-by-step explanation:

(-6x^2 y^8+12xy^3-36xy^2)

6xy^2

Divide each term by 6 in the numerator and denominator

(-6/6x^2 y^8+12/6xy^3-36/6xy^2)

6/6xy^2

-x^2y^8 +2xy^3 -6xy^2

xy^2

Divide each term by x in the numerator and denominator

-x^2/xy^8 +2x/xy^3 -6x/xy^2

x/xy^2

-xy^8 +2y^3 -6y^2

y^2

Divide each term by y^2 in the numerator and denominator

Remember when dividing, we subtract the exponents

-xy^8/y^2 +2y^3/y^2 -6y^2/y^2

y^2 /y^2

-xy^6 +2y^1 -6

1

-xy^6 +2y -6

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!