Mathematics, 23.06.2019 08:30, destinyhammons12345

Giovanna, frances, and their dad each carried a 10 lb bag of soil into the backyard. after putting soil in their first flower bed, giovanna's bag was 5/8 full frances bag to was 2/5 full, and their dads was 3/4 full. how many pounds of soil did they put in their first flower bed all together

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answered: merunikitty1226

12.25 pounds

Step-by-step explanation:

Given : Giovanna,Frances,and their dad each carried a 10 lb bag of soil into the backyard. After putting soil in their first flower bed, giovanna's bag was 5/8 full Frances bag to was 2/5 full,and their dads was 3/4 full.

To Find: . How many pounds of soil did they put in their first flower bed all together?

Solution :

Since each carried a 10 lb bag of soil into the backyard

After putting soil in their first flower bed, giovanna's bag was 5/8 full

So, amount he poured in the first flower bed =

= $10(1-\frac{5}{8})$

= $10(\frac{3}{8})$

= $\frac{30}{8}$

= $\frac{15}{4}$

So, amount giovanna poured = 15/4 lb

Frances bag to was 2/5 full,

amount he poured in the first flower bed =

= $10(1-\frac{2}{5})$

= $10(\frac{3}{5})$

= $\frac{30}{5}$

So, amount Frances poured = 6 lb

their dads was 3/4 full.

amount he poured in the first flower bed =

= $10(1-\frac{3}{4})$

= $10(\frac{1}{4})$

= $\frac{10}{4}$

= $]\frac{5}{2}$

So, amount Frances poured = 5/2 lb

So,they put soil in their first flower bed all together :

$\frac{15}{4} +6+\frac{5}{2}$

=12.25 lb

Hence they put 12.25 pounds of soil in their first flower bed all together

answered: acavalieri72

12.25 pounds sand.

Step-by-step explanation:

We have been given that Giovanna,Frances,and their dad each carried a 10 lb bag of soil into the backyard.

After putting soil in their first flower bed, Giovanna's bag was 5/8 full. This means she put 3/8 of 10 pounds in the flower bed.

$\text{Giovanna put sand in the flower bed}=\frac{3}{8}\times 10$

$\text{Giovanna put sand in the flower bed}=3\times 1.25$

$\text{Giovanna put sand in the flower bed}=3.75$

Therefore, Giovanna put 3.75 pounds of sand in the 1st flower bed.

Frances's bag was 2/5 full. This means that he put 3/5 of 10 pounds sand in the flower bed.

$\text{Frances put sand in the flower bed}=\frac{3}{5}\times 10$

$\text{Frances put sand in the flower bed}=3\times 2$

$\text{Frances put sand in the flower bed}=6$

Therefore, Frances put 6 pounds sand in the flower bed.

Their dad's bag was 3/4 full. This means that their dad put 1/4 of 10 pounds sand in the flower bed.

$\text{Dad put sand in the flower bed}=\frac{1}{4}\times 10$

$\text{Dad put sand in the flower bed}=2.5$

Therefore, dad put 2.5 pounds sand in the flower bed.

Let us add the amount of sand put by each person to find the total amount of sand in the flower bed.

$\text{The amount of sand in the flower bed}=3.75+6+2.5$

$\text{The amount of sand in the flower bed}=12.25$

Therefore, they put 12.25 pounds of sand in their first flower bed all together.

answered: Guest

false

step-by-step explanation:

false. two legs of the trapezoid would be congruent, but the other two would not. were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

answered: Guest

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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