Given 1+tanx/1+cotx=2, find a numerical value of one trigonometric function of x.

tanx = 2

Step-by-step explanation:

Given (1 + tanx) / (1 + cotx) = 2

Using the formula:- cotx = 1 / tanx.

Change cotx into tanx in the equation:-

(1 + tanx) / (1 + 1/tanx) = 2

(1 + tanx) / {(tanx + 1) / tanx} = 2

Keep Numerator as it is, Change division to multiplication, Flip denominator:-

{ (1 + tanx)/1 } * { tanx/(tanx + 1) } = 2

tanx * (1 + tanx) / (tanx + 1) = 2

tanx = 2

Hence, the answer is tanx = 2.

Its B. tanx=2 on ed

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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