Which of the following is a solution to the system of equations? y= 3x-2 6 + y=-x

x=-1  y = -5

Step-by-step explanation:

y= 3x-2  

6 + y=-x

Substitute the first equation into the second equation

6 +y =-x

6+ (3x-2) = -x

Combine like terms

4 + 3x = -x

Subtract 3x from each side

4 +3x -3x = -x -3x

4 = -4x

Divide by -4

4/-4  = -4x/-4

-1 =x

Now we need to find y

y= 3x-2

y = 3(-1) -2

  = -3-2

   = -5

(-1, -5)

Step-by-step explanation:

We can solve this system using substitution.  y = 3x - 2, so replace "y" in the second equation with "3x - 2:"

6 + (3x - 2) = -x, or 6 + 3x - 2 = -x

Group like terms together:  3x + x = -6 + 2.

Then 4x = -4, and x = -1.

Subst. -1 for x in the first equation:  y = 3(-1) - 2, or y = -5.

Then the solution is (-1, -5).

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: