What is the point-slope form of a line that has a slope of 3 and passes through the point (–1, 4)? y  – (–1) = 5(x  – 4)4 –  y1  = 3(–1 –  x1)y  – 3 = –1[(x  – (–4)]y  – 4 = 3[(x  – (–1)]

D

Step-by-step explanation:

The equation of a line in point-  slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 3 and (a, b) = (- 1, 4), hence

y - 4 = 3( x - (- 1)) which simplifies to

y - 4 = 3(x + 1)

D. y-4=3[(x-(-4)]

Step-by-step explanation:

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let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled