Its all one big question h(x) = x2 + 1 k(x) = x – 2 (h + k)(2) = ? (h – k)(3) = ? evaluate 3h(2) + 2k(3) = ?

see explanation

Step-by-step explanation:

h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

h(x) - k(x) = x² + 1 - (x - 2) = x² + 1 - x + 2 = x² -x + 3

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

3h(2) + 2k(3) = (3 × 5) + (2 × 1) = 15 + 2 = 17

(h + k)(2) = 5, (h – k)(3) =9 and 3h(2) + 2k(3) = 17.

Step-by-step explanation:

The given functions are

First find the values of functions at x=2 and x=3.

At x=2,

At x=3,

Now, use these values to find the required values.

Therefore, (h + k)(2) = 5, (h – k)(3) =9 and 3h(2) + 2k(3) = 17.

goog may have it for you

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70