State all values of x in the interval 2 ≤ x ≤ 8 that satisfy the following inequality: 3x + 5 > 14 me. i desperately need it. show your work as well, because don't get this at all.

3x+5 > 14

3x+5-5 > 14-5 ... subtract 5 from both sides

3x > 9

3x/3 > 9/3 .... divide both sides by 3

x > 3

So x can be any number larger than 3

We're also told that meaning x is between 2 and 8 (including both endpoints).

Overlap these two intervals, and you'll get this new compound inequality: so x can be larger than 3, and smaller than 8. It cannot be equal to 3, but it can equal 8. It can equal any number between 3 and 8.

If x is a whole number, then the following values are solutions: {4, 5, 6, 7, 8} so basically anything from 3 to 8, excluding 3 but including 8.

If x is a real number, then you simply write

note: if x is a real number, then the answer in interval notation is (3, 8]. The curved parenthesis says "exclude this endpoint" and the square bracket means "include this endpoint".

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

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step-by-step explanation: