Is this the correct way to solve 2x < x + 2 ≤ 3x + 5? 2x - 3 < x + 2 -x -x x - 3 < 2 + 3 + 3 x < 5 x + 2 ≤ 3x + 5 -x -x 2 ≤ 2x + 5 -5 -5 -3 ≤ 2x /2 /2 -3/2 ≤ x -3/2 ≤ x < 5 : )

sorr dk

Step-by-step explanation:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

step-by-step explanation: