What is the solution set of the quadratic inequality 6x^2+ 1 is less or equal to zero

There are no solutions to that inequality.

Step-by-step explanation:

Without actually doing any operations on the inequality, just by giving it a good look: you will see that there no way, for any x, negative or positive, that the expression will become negative or zero. x^2 is always non-negative, and the +1 bias ensures the expression will never ever, like, n-e-v-e-r, be anything but positive.

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Step-by-step explanation:

your welcome

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: