Agoblet contains 333 red balls, 222 green balls, and 666 blue balls. if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

Step-by-step explanation:

A goblet contains 3 red balls, 2 green balls and 6 blue balls.

Total balls = 3 + 2 + 6 = 11 balls

we choose a ball and then another ball without putting the first one back.

The probability that the first ball will be red = =

Second event is done without replacing the first ball so total ball will be 10

The probability that the second ball will be blue = = =

P = × =

The probability that the first ball will be red and the second ball will be blue is

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2