Ineed to know the values of x that are not in the domain of h.

x = - 7, + 7

Step-by-step explanation:

The denominator of h(x) cannot be zero as this would make h(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

solve :

x² - 49 = 0 ⇒ (x - 7)(x + 7) = 0 ⇒ x = ± 7

The domain is valid for all x ∈ R , x ≠ - 7, + 7

10000000000000000000000000000000

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14