The perimeter of a rectangle is 141 feet, and the length is twice the width. what are the dimensions of the rectangle?

Using a system of equations from the equation of a rectangle's perimeter, it is found that:

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The perimeter of a rectangle of length l and width w is given by:

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The perimeter of a rectangle is 141 feet

This means that:

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Length is twice the width

This means that

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Finding the width:

Replacing into the first equation:

The width of the rectangle is of 23.5 feet.

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The length is:

The length of the rectangle is of 47 feet.

A similar problem is given at link

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

idk

step-by-step explanation: