An angle measuring (870n)° is in standard position. for which value of n will the terminal side fall on the y-axis? n = 3 n = 4 n = 5 n = 6

The answer is n=3

Step-by-step explanation:

Given that an angle measuring (870n)° is in standard position.

we have to find the value of n for which the terminal side fall on the y-axis.

If it can written in the form of (90°)a, where a is any positive odd integer.

The terminal side fall on y-axis when a is positive odd integer.

Here, the given angle is (870n)°,

For n = 3,

Our angle will be 2610°

Its terminal side fall along the positive portion of the y-axis,

If 2610° = (90°)a ⇒ a = 29 ( Positive odd integer )

Thus, for n = 3,  the terminal side of the angle (870n)° falls along the positive portion of the y-axis,

For n = 4,

Our angle will be 3480°

Its terminal side fall along the positive portion of the y-axis,

If 3480° = (90°)a ⇒ a = 38.6667 ( Not possible )

Thus, for n = 4, the terminal side of the angle (870n)° does not fall along the positive portion of the y-axis

For n = 5,

Our angle will be 4350°

Its terminal side fall along the positive portion of the y-axis,

If 4350° = (90°)a ⇒ a = 48.333.. ( Not possible )

Thus, for n = 5,  the terminal side of the angle (870n)° does not fall along the positive portion of the y-axis,

For n = 6,

Our angle will be 5220°

Its terminal side fall along the positive portion of the y-axis,

If 5220° = (90°)a ⇒ a = 58 ( Not possible )

Thus, for n = 6,  the terminal side of the angle (870n)° does not fall along the positive portion of the y-axis.

n = 3

Step-by-step explanation:

right on edg

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: )

step-by-step explanation:

i am unable to solve this problem

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