The graph of f(x) = 2x^2 + 20x + 48 is showna. write the equation in intercept form by factoring. b. what are the x-intercepts of the graph? what are the zeros of the function? what are the roots of the function? c. what are the solutions of 2x^2 + 20x + 48 = 0

a) The equation in intercept form by factoring is (x+6)(x+4)

b) From the given graph x- intercepts are (-4,0) and (-6,0) and zeros (roots) of the function are -6 and -4.

c) The solutions of   is that is x= -6 and x = -4.

Step-by-step explanation:

The given quadratic  equation is

Put the function f(x) = 0 , then

a) The equation in intercept form by factoring is ,

Consider the given function,

taking 2 common, we get,

The above is a quadratic equation of the form

Solving quadratic equation using middle term splitting method,

Thus, The equation in intercept form by factoring is (x+6)(x+4).

b) From the given graph x- intercepts are (-4,0) and (-6,0) .

Zeroes / roots of a function are those points where the value of the function is zero.

Put f(x) = 0  as solved above

that is

or

or

Thus, zeros (roots) of the function are -6 and -4.

For checking put x = -6 and -4 in the function we get f(x) =0 .

c) The solutions of   is that is x= -6 and x = -4 as shown above.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: