Find the vertex of the parabola y=x^2 — 2x + 3/10

The vertex would be (1, -7/10)

Step-by-step explanation:

In order to find the vertex, start by finding the x-coordinate. The x-coordinate can be calculated using -b/2a, in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-(-2)/2(1)

2/2

1

Now that we know the value of the x-coordinate as 1, we can use it in the equation to find y.

y = x^2 - 2x + 3/10

y = (1)^2 - 2(1) + 3/10

y = 1 - 2 + 3/10

y = -7/10

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this