Mathematics

Mathematics, 24.06.2019 16:00, lilwolves1013osqd2o

Solve for y in terms of m by cross-multiplying. $\frac{y}{m} =\frac{1}{3}$

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Mathematics, 23.06.2019 07:00, camillexv2668

A.solve [tex]\frac{1}{n} \pi = \theta - \frac{1}{2}sin(2 \theta)[/tex] for [tex] \theta[/tex] in terms of "n"(derivation of equation below)b. based on your answer inpart a, if [tex] \theta = arccos(1 - \frac{a}{r} ) = {cos}^{ - 1} (1 - \frac{a}{r} )[/tex] or [tex] a = r-2cos( \theta)[/tex]find "a" as a function ofr & n. (find f(r,n)=a).alternately, if a+b=r, we can write [tex] \theta = arccos( \frac{b}{r} ) = {cos}^{ - 1} (\frac{b}{r} )[/tex] then solve for "a" in terms of r and nshow all work and reasoning.solve analytically if possible

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English, 24.06.2019 00:30, dayana72

What do the fourth, fifth, sixth, seventh, and eighth amendments guarantee for citizens? ability to bear arms freedom of speech a fair trial right to vote[tex]\frac{x}{y}\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{xfdddddddddddddddddddddddddddddddd}{y}[/tex]

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Mathematics, 14.07.2019 01:30, wiintrr30

[tex] \frac{(a-3) * (\frac{a}{3} +1)}{\frac{1}{3}} [/tex] [tex] \frac{a( \frac{a}{3} ) + a - 3(\frac{a}{3}) - 3 }{\frac{a}{3}} [/tex] [tex] \frac{\frac{3a+a}{3} + a - 3 * \frac{a}{3} - 3}{\frac{1}{3}} [/tex] [tex] \frac{\frac{4a}{3} + a - a - 3}{\frac{1}{3}} [/tex] [tex] \frac{4a}{3} / \frac{1}{3} - 3 / \frac{1}{3} [/tex] [tex] \frac{4a}{3} * 3 - 3 * 3 [/tex] [tex] 4a - 9 [/tex] yet the answer i should get is [tex] a^{2}-9 [/tex]. what step am i doing wrong on this algebra problem?

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Mathematics, 06.09.2019 05:10, jibjabsalar1212

Report error find the sum of the series 1 + \frac{1}{2} + \frac{1}{10} + \frac{1}{20} + \frac{1}{100} + \cdots, where we alternately multiply by \frac 12 and \frac 15 to get successive terms.

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Solve for y in terms of m by cross-multiplying.[tex]\frac{y}{m} =\frac{1}{3}[/tex]...

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