Find the 4th term of the expansion of (2a-b)^7

-560a^4b^3 .

Step-by-step explanation:

For a binomial expansion :

(r + 1)th term of (a + b)^n = nCr a^(n-r) b^r.

So the 4th term of (2a - b)^7

= (3 + 1)th term = 7C3 (2a)^(7-3) (-b)^3

= 35 * 16a^4* -b^3

= -560a^4b^3  (answer).

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0