The volume of construction work was increased by 60% but the productivity of labor increased by only 25%. by what percent must the number of workers be increased in order for the work to be completed in time, as it was scheduled originally?

 28 %

Step-by-step explanation:

Since, Volume of a work = productivity × time × number of workers

Let V be the initial volume of the work , p is the initial productivity , n is the initial time and x be the initial number of workers.

Then, V = p × N × x ------ (1)

When, the volume of construction work was increased by 60%, productivity of labor increased by only 25% and time remains same,

Let y be the new number of workers,

Then, 1.6 V = 1.25 p × N × y -------(2)

Dividing equation (1) by equation (2)

We get,

Thus, the percentage increase in the number of workers =

Therefore, the number of workers is increased by 28%.

The number of number of workers is increased by 28%.

Step-by-step explanation:

Let the volume of construction work be v

Let the productivity of labor be p.

Let the number of workers be n.

So, our original equation becomes

Now,

According to question, we have given that if volume increased by 60% and the productivity increases by 25%.

Let the percentage increase in number of workers be x

So, it becomes,

So, The number of number of workers is increased by 28%.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the correct option is b

step-by-step explanation: