Find the expected value of a random variable x having the following probability distribution. x (-5,-1,0,1,5,8) probability (.12, .16, .28, .22, .12, .1)

The expected value is 0.86.

Step-by-step explanation:

To find the expected value, multiply each x value by the corresponding probability, and then sum up these products:

(-5)(0.12) + (-1)(0.16) + (0)(0.28) + 1(0.22) + 5(0.12) + 8(0.10).

This comes out to

-0.60 - 0.16 + 0 + 0.22 + 0.60 + 0.8 = 0.86

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: