Each t-shirt sells for $8, and each long-sleeve shirt sells for $11. the swim team collected $310 for the 35 shirts that were sold. how many of each type of shirt were sold? t = t-shirts & s = long sleeve shirts which system of equations could be used to solve this problem? a. 8t + 11s = 310 t + s = 35 b. 11t + 8s = 310 t + s = 35 c. 11t + 8s = 35 t + s = 310 d. 8t + 11s = 35 t + s = 310

Number of T shirt sold = 25

Number of long-sleeve shirt sold = 10

Option A is the correct answer.

Step-by-step explanation:

Let the number of T shirt be t and long-sleeve shirt be s.

We have cost of T shirt = 8$ and cost of long-sleeve shirt = 11 $.

Total number of shirts sold = 35

                 t + s = 35    Equation 1

Dollar collected = 310 by selling 35 shirts = 310 $

                 8 t + 11 s = 310    Equation 2

Equation 1 x 8

                8 t + 8 s = 8 x 35 = 280    Equation 3

Equation 2 - Equation 3

            8 t + 11 s - 8 t - 8 s = 310 - 280 = 30

                     3 s = 30

                        s = 10

Substituting in equation 1

                t + 10 = 35

                t = 25

Equations are 8t + 11s = 310 and t + s = 35

Number of T shirt sold = 25

Number of long-sleeve shirt sold = 10

Option A is the correct answer.

29933333.33

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116