Mathematics, 25.06.2019 08:00, Lindy4886

Determine if segments ab and cd are parallel, perpendicular, or neither 1. line ab formed by a(-1,3) and b(1,5); line cd formed by c(2,3) and d(-2,7) 2. line ab formed by a(3,8) and b(-6,5); line cd formed by c(-6,7) and d(-3,8) 3. line ab formed by a(2,-7) and b(2,3); line cd formed by c(-4,0) and d(-4,-5)

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answered: help26852

1 is perpendicular

2 is parallel

3 is parallel

Step-by-step explanation:

yeah

answered: animegirl02

1: perpendicular.

2 and 3: parallel.

Step-by-step explanation:

Given line segment AB and CD, in each part we have to find the slope in order to find the nature i.e these are parallel, perpendicular, or neither

we know Two lines are parallel if they have same slope, perpendicular if their slopes are negative reciprocals.

1. Line AB formed by A(-1,3) and B(1,5); Line CD formed by C(2,3) and D(-2,7)

Slope of AB is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{5-3}{1-(-1)}=1$

Slope of CD is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{7-3}{-2-(2)}=-1$

The slopes of above two are negative reciprocals. Hence, the lines are perpendicular.

2. Line AB formed by A(3,8) and B(-6,5); Line CD formed by C(-6,7) and D(-3,8)

Slope of AB is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{5-8}{-6-(3)}=\frac{1}{3}$

Slope of CD is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{8-7}{-3-(-6)}=\frac{1}{3}$

The slopes of above two are equal. Hence, the lines are parallel.

3. Line AB formed by A(2,-7) and B(2,3); Line CD formed by C(-4,0) and D(-4,-5)

Slope of AB is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{3+7}{2-2}=\infty$

Slope of CD is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{-5-0}{-4+4}=\infty$

The slopes of above two lines are undefined. Hence, these are vertical lines therefore parallel.

answered: Guest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

answered: Guest

the above table 1 will calculate the population size (n) after a certain length of time (t). all you need to do is plug in the initial population number (no), the growth rate (r) and the length of time (t). the constant (e) is already entered into the equation. it stands for the base of the natural logarithms (approximately 2.71828). growth rate (r) and time (t) must be expressed in the same unit of time, such as years, days, hours or minutes. for humans, population growth rate is based on one year. if a population of people grew from 1000 to 1040 in one year, then the percent increase or annual growth rate is 40/1000 x 100 = 4 percent.

step-by-step explanation:

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Determine if segments ab and cd are parallel, perpendicular, or neither 1. line ab formed by a(-1,3...