If (6^2)^x =1 what is the value of x

x = 0

Step-by-step explanation:

Rewrite (6^2)^x =1 as 6^(2x) = 1.

Next, take the logarithm (common or natural) of both sides, obtaining

2x log 6 = log 1

2x log 6 = 0

Then x = 0.

Note that (6^2)^0 = 1, since any positive number raised to the prower 0 is 1.

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