Astore has two types of nuts that they will mix together to make a mixture worth $5.45 per pound. if the store uses 11 pounds of a nut that costs $3.60 per pound, how many of pounds of nuts that cost $6.80 per pound should be added to make the mixture?

about 15.07 pounds

Step-by-step explanation:

Let n represent the number of pounds of higher-priced nuts required. Then the total cost of the mixture will be ...

  3.60·11 + 6.80n = 5.45(11 +n)

  39.60 +6.80n = 59.95 +5.45n . . . . . . eliminate parentheses

  1.35n = 20.35 . . . . . . . . . . . . . . . . . . . . add (-5.45n -39.60)

  20.35/1.35 = n ≈ 15.07 . . . . . . . . . . . . divide by the coefficient of n

About 15.07 pounds of nuts that cost $6.80 per pound should be added to make the mix.

is there any photos or whatever?

300pi

step-by-step explanation: