Mathematics, 25.06.2019 15:30, uuytay
The coordinates of point a are (-6, -10) and the coordinates of point b are (x,-4). the distance between a to point b is 10 units. find the x-coordinate of point b if b lies in the fourth quadrant.
Answers: 1
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-10})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{-4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ 10=\sqrt{[x-(-6)]^2+[-4-(-10)]^2}\implies 10=\sqrt{(x+6)^2+(-4+10)^2} \\\\\\ 10^2=(x+6)^2+(6)^2\implies 100=x^2+12x+36+36 \\\\\\ 100=x^2+12x+72\implies 0=x^2+12x-28 \\\\\\ 0=(x+14)(x-2)\implies x= \begin{cases} -14\\ \boxed{2} \end{cases}](/tpl/images/0016/1389/9f281.png)
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The coordinates of point a are (-6, -10) and the coordinates of point b are (x,-4). the distance bet...
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