Determine which of the following equations, when graphed, intersect at the point (4, 0). select all that apply. x - y = 4 -x - y = 4 2x - y = 7 x + y = 4 2x + y = 7 2x + y = -7

Hence, the following equations, when graphed, intersect at the point (4, 0):

x - y = 4 (1)

x + y = 4 (4)

Step-by-step explanation:

" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".

1)

x-y=4

now when y=0 then x=4.

Hence, the graph intersect at the point (4,0).

2)

-x-y=4

When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.

3)

2x-y=7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

4)

x+y=4

When y=0 then x=4.

Hence the graph of the given function intersect at (4,0).

5)

2x + y = 7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

6)

2x + y = -7

When y=0 then x= -7/2.

Hence the graph of the function does not intersect at the point (4,0).

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?