Aplane leaves jfk international airport and travels due west at 570 mi/hr. another plane leaves 20 minutes later and travels 22° west of north at the rate of 585 mi/h. to the nearest ten miles, how far apart are they 40 minutes after the second plane leaves. attach a picture if convenient.

557 miles

Step-by-step explanation:

Plane 1

It travels for 60 minutes (20+40) = 1 hour

Distance = 1 hour* 570 mph =  570 miles  in a negative x direction

(-570,0)

Plane 2

travels 40 minutes = 2/3 hour

Distance = 2/3 * 585 mph = 390 miles

-x direction = 390 sin 22

y direction = 390 cos 22

(-390 sin22, 390 cos22)

distance = sqrt ((x2-x1)^ + (y2-y1)^2)

              = sqrt( (-390 sin22 - -570)^2 + (390cos22)^2)

              = sqrt((-390 sin22 +570)^2 + (390cos22)^2)

              = sqrt( 423.9034286^2 +361.6017033^2)

              =sqrt(31044909086)

               =557.18031961590

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336